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The energy required to melt 1g. ice is 33j.The number of quanta of radiation of frequency 4.67×10 sec that must be absorbed to melt 10g ice is

Eshan
3 years ago
Dear student,

Energy of each quanta =$\dpi{80} h\nu$

$\dpi{80} \implies nh\nu=E$
Energy required to melt 10g of ice=$\dpi{80} 10\times 33J=330J$

Hence$\dpi{80} n=\dfrac{E}{h\nu}$

The value of frequency is not correctly given, but the above relation can provide the answer.

Hope it helps.