The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)
a. -3.4 e V
b. -4.2 e V
c. -6.8 e V
d. +6.8e V
Amit Saxena
12 Years agoGrade upto college level
1 Answer
Navjyot Kalra
12 Years ago
Sol. Energy of electron in H-atom is determined by the expression
E_n = 13.6/n^2 eV where, n = 1, 2, 3,….
In excited states, E_2 = - ( 13.6)/4 = - 3.4 eV
E_3 = ( 13.6)/9 = - 1.51 eV etc.