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the electron affinity of chlorine is 3.9ev how much energy in KCAl is released when 2g of chlorine is completely converted to cl- ion in gaseous state

Bharadwaj Varma , 9 Years ago
Grade 12
anser 1 Answers
Vikas TU
write the eqn.
Cl2        +       2e-        ----------->>>           2Cl-
2/71 moles                    would give             2/71*2 = > 1/71 moles.    
For 2 elctrons,
Energy = 3.9 * 2 /71 = >0.109 eV.
 = 0.109 * 1.6022 * 10^-22
 = 0.17676 * 10^-22 Kcalories.
Last Activity: 9 Years ago
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