The diameter of a bubble at the surface of lake is 4mm and at the bottom of the lake is 1mm . if atmospheric pressure is 1 ATM and the temperature of the lake water is equal to that of atmosphere. What is cut he depth of the lake?

Question

Vikas TU · Answer

Use simple ideal eqn. that is from charles law, P1V1/T1 = P2V2/T2...............(1) At the surface, P1 = 1 atm. V1 = 4pi*(4)^2 and At the bottom P2 = 1 atm + pgh = > 1 + (1000*9.8*h)/10^5 atm V2 = 4pi*1^2 Put all the values in eqn. (1) with temp. same, we get, 16 = 1+ 0.098h h = 153.03 meter.

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The diameter of a bubble at the surface of lake is 4mm and at the bottom of the lake is 1mm . if atmospheric pressure is 1 ATM and the temperature of the lake water is equal to that of atmosphere. What is cut he depth of the lake?

The diameter of a bubble at the surface of lake is 4mm and at the bottom of the lake is 1mm . if atmospheric pressure is 1 ATM and the temperature of the lake water is equal to that of atmosphere. What is cut he depth of the lake?

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