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The diameter of a bubble at the surface of lake is 4mm and at the bottom of the lake is 1mm . if atmospheric pressure is 1 ATM and the temperature of the lake water is equal to that of atmosphere. What is cut he depth of the lake?
Use simple ideal eqn. that is from charles law,P1V1/T1 = P2V2/T2...............(1)At the surface,P1 = 1 atm.V1 = 4pi*(4)^2andAt the bottomP2 = 1 atm + pgh = > 1 + (1000*9.8*h)/10^5 atmV2 = 4pi*1^2Put all the values in eqn. (1) with temp. same,we get, 16 = 1+ 0.098hh = 153.03 meter.
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