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Grade 11Physical Chemistry

The density of a solution prepared by dissolving 120g of urea (mol.mass =60u) in 1000th of water is 1.15g/ml. The molarity of the solution is

Profile image of Yashika Kothari
7 Years agoGrade 11
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer7 Years ago
Molarity = Number of moles of solute/Volume of solution in Litres
Moles of urea = Given mass/Molecular mass = 12060 = 2 mol
Volume of solution = Mass of solution/Density of solution= (120+1000) g/1.15 g.mL−1= 974 ml or 0.974 L
Hence, Molarity = 2 mol/0.974 L = 2.05 mol L−1