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The degree of dissociation (?) of a weak electrolyte, AxBy is related to van’t Hoff factor(i) by the expression

The degree of dissociation (?) of a weak electrolyte, AxBy is related to van’t Hoff factor(i) by the expression

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2 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
7 years ago
The degree of dissociation (?) of a weak electrolyte, AxBy is related to van’t Hoff factor(i) by the expression
204-1657_Tue Aug 19 02-36-22.jpg
Kushagra Madhukar
askIITians Faculty 629 Points
one year ago
Dear student,
Please find the solution to your problem.
 
AxBy → xAy+ + yBx-
Hence, van’t hoff factor, i = 1 + (x + y – 1)a
or, a = (i – 1)/(x + y – 1)
 
Thanks and regards,
Kushagra

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