Physical ChemistryThe degree of dissociation (?) of a weak electrolyte, AxBy is related to van’t Hoff factor(i) by the expression nikhil 12 Years agoGrade
Sunil Kumar FP11 Years agoThe degree of dissociation (?) of a weak electrolyte, AxBy is related to van’t Hoff factor(i) by the expression
Kushagra Madhukar5 Years agoDear student,Please find the solution to your problem. AxBy → xAy+ + yBx-Hence, van’t hoff factor, i = 1 + (x + y – 1)aor, a = (i – 1)/(x + y – 1) Thanks and regards,Kushagra