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CaCO3➡️CaO + CO2
HereCO2 produced is 11.2 ÷22.4 =0.5mole
CO2+2KOH➡️K2CO3+H2O
1 mole CO2 requires 2 mole KOH
So 0.5 mole CO2 will require 1 mole KOH
Mass of KOH required = 1× 56= 56 gram
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