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The composition of a sample of wustite is Fe_0.93O_1.00. What percentage of the iron is present in the form of Fe (III)?

Amit Saxena

12 Years agoGrade upto college level

2 Answers

Navjyot Kalra

12 Years ago

In pure iron oxide (FeO), iron and oxygen are present in the ratio 1 : 1.

However, here number of Fe²⁺ present = 0.93

Or No. of Fe²⁺ ions missing = 0.07

Since each Fe²⁺ ion has 2 positive charge, the total number of charge due to missing (0.07) Fe²⁺ ions = 0.07 * 2 = 0.14

To maintain electrical neutrality, 0.14 positive charge is compensated by the presence of Fe³⁺ ions. Now since, replacement of one Fe²⁺ ion by one Fe³⁺ ion increases one positive charge, 0.14 positive charge must be compensated by the presence of 0.14 Fe³⁺ ions.

In short, 0.93 Fe²⁺ ions have 0.14 Fe³⁺ ions

100 Fe²⁺ ions have = 0.14/0.93 * 100 = 15.05%

Kushagra Madhukar

6 Years ago

Dear student,

Please find the attached solution to your question.

let us take x be the number of Fe³⁺ ions in 100moles of Fe_0.93O₁

Hence, moles of Fe²⁺ = 100 x 0.93 – x = 93 – x

Since it is a neutrally charged compound.

The net charge on it will be balanced

Hence, 2(93 – x) + 3x = 2 x 100

186 + x = 200

or, x = 14

Hence percentage of Fe³⁺ = 14/93 x 100 = 15.05%

Hope this helps.

Thanks and regards,

Kushagra

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