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# The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. Kb for benzene is 2.53 K kg mol–1

Sakshi
5 years ago
One can use the fact for the elevation in boiling point on the addition of a non-volatile solute.
The equation to be used is

Jerin A Varghese
15 Points
one year ago
Tb = 354.11 K
T0= 353.23 K
Kb = 2.53 K
wsolute  = 1.8 g
wsolvent  =90 g
$\Delta$T = Tb - T0
=354.11 – 353.23
=0.88 K

$\Delta$T =  Kb x wsolute  ÷ wsolvent  x  Mo
M=  2.53 K x 1.8 g  90 g x 0.88 K
= 0.0575 kg/mol
= 57.5 g/mol
= 58 g/mol