0

Guest

Courses New

The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. Kb for benzene is 2.53 K kg mol–1

The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. Kb for benzene is 2.53 K kg mol–1

Grade:11

2 Answers

Sakshi
askIITians Faculty 652 Points
8 years ago
One can use the fact for the elevation in boiling point on the addition of a non-volatile solute.
The equation to be used is
\Delta Tb= K_{b} * molality
Jerin A Varghese
15 Points
4 years ago
Tb = 354.11 K
T0b = 353.23 K
Kb = 2.53 K
wsolute  = 1.8 g
wsolvent  =90 g
\DeltaTb  = Tb - T0b 
          =354.11 – 353.23
         =0.88 K
 
\DeltaTb  =  Kb x wsolute  ÷ wsolvent  x  Mo
 Mo =  2.53 K x 1.8 g  90 g x 0.88 K 
       = 0.0575 kg/mol
       = 57.5 g/mol
      = 58 g/mol
 
 
 

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More