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Grade: 12
        The boiling point of 0.1 Molal K4[Fe(CN)6] solution will be ( given Kb for water = O.52°C kg/mol)
2 years ago

Answers : (1)

Arun
23478 Points
							
Dear student
K4 [Fe (CN)6] gives 5 ions(i)
 ∆Tb= i kb m= 5X 0.52 X0.1=0.26, 
Tb=100+0.26=100.26 °C
 
Regards
Arun (askIITians forum expert)
2 years ago
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