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Grade 12Physical Chemistry

The boiling point of 0.1 Molal K4[Fe(CN)6] solution will be ( given Kb for water = O.52°C kg/mol)

Profile image of Rutik
8 Years agoGrade 12
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1 Answer

Profile image of Arun
8 Years ago
Dear student
K4 [Fe (CN)6] gives 5 ions(i)
 ∆Tb= i kb m= 5X 0.52 X0.1=0.26, 
Tb=100+0.26=100.26 °C
 
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Arun (askIITians forum expert)