Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        the average velocity at T1k and most propable velocity at T2k of co2 gas is9.0*104cm sec caluculate the values of T1and T2`
one year ago

Arun
23345 Points
```							Average velocity = √8RT/πMand Most probable velocity = √2RT/MGiven –For CO2Average velocity at T1 Most probable velocity at T2= 9 * 104cm/sec = 9 * 104/100 m/sec.= 9 * 102= m/sec.∴ 9 * 102= √8 * 8.314 9 T1/3.14 *44 * 10-3 …..(A)[Average velocity at T1K]and 9 * 102= √2 * 8.314 * T2/44 * 10-3 …..(B)[Most probable velocity at T2]On solving, T1 = 1682.5 K, T2 = 2143.4 K
```
one year ago
Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions