Grade 12Physical ChemistryThe average K.E of an ideal gas In calories per mole is approximately equal to: Rea Shejith 9 Years agoGrade 12
Vikas TU9 Years agoThe average K.E of an ideal gas In calories per mole is approximately equal to: Every atoms is associated with an avergae kinetic energy as => 3KT/2From the PV = nRTn = PV/RT.
Prafulla patil7 Years agoWe know that, K.E=3/2nRTR=2 cal mol^-n=1Therefore, K.E=3/2*2*TK.E=3TThai is, 3 times a absolute temp