Grade 12th passPhysical Chemistry
The atomic radius of CR is .1249nm and it has a bcc structure . what is the free volume per unit cell?
1 Answer
Sakshi
hey student..
for this question you need to use the basic general formula for the body centred cubic unit cell
The relationship between a and R can be worked out by the Pythagorean theorem:(4 R)2 = 3 a2
Thus,
4 R = sqrt(3) a
or
a = 4R/sqrt(3)
Well, this means you should calculate the percentage of the volume occupied by the spheres in the packing. Packing fraction = Vsphere / Vunit cell
= 2*4/3 p R3 / (4/sqrt(3) R3)
= Ö3 p / 8 = 0.6802
nou u know the packing fraction, subtracting it from 1 you can get the empty space also
for this question you need to use the basic general formula for the body centred cubic unit cell
The relationship between a and R can be worked out by the Pythagorean theorem:(4 R)2 = 3 a2
Thus,
4 R = sqrt(3) a
or
a = 4R/sqrt(3)
Well, this means you should calculate the percentage of the volume occupied by the spheres in the packing. Packing fraction = Vsphere / Vunit cell
= 2*4/3 p R3 / (4/sqrt(3) R3)
= Ö3 p / 8 = 0.6802
nou u know the packing fraction, subtracting it from 1 you can get the empty space also
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