The absorption of energy by an atom of hydrogen in ground state,results in the ejection of the electron with the de Broglie wavelength = 4.7 * 10^-10 m. Given that the ionization energy is 13.6 ev, Calculate the energy of the photon which caused the ejection of electron
Joshua Sama , 5 Years ago
Grade 11
1 Answers
nikhilesh
Last Activity: 5 Years ago
the energy of photon is equal to ionisation energy plus energy of emeted electron
therefore the answer is 13.6+p^2/2m
=13.6+h^2/2mL^2( lis wave lenth)
on substuting the values we get aswer as 40.2eV.
hope it clears.
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