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question mark

System A and system B above are identical closed
systems that undergo a change of state from the
same initial conditions (P1, V1, T1) to the same
final conditions (P2, V2, T2), but by a different
process. What are DU and q for the change in
state for system B?

Bxt , 6 Years ago
Grade 12th pass
anser 2 Answers
Kapil Khare
Work Done in system A = W = -300J
Since, system A has gone through adiabatic process,
Heat transfer in system A = q = 0
Change in internal energy of A = W =  -300J
 
Since, initial and final condition of A and B are same,
Change in internal energy of A = change in internal energy of B
\implies Change in internal energy of B = -300
 
For system B,
q + W = change in internal energy of B
-200 + q = -300
\implies Heat transformmed = q = -100
Last Activity: 6 Years ago
Rajdeep
HELLO THERE!
 
The foremost concept that is going to be used in the question is that, Internal energy is a state function, that does not depend on the path (process) of the system, but on the initial and final state of the system.
 
For A, the process is Adiabatic, so heat exchance Q = 0.
U = Q + W (From First Law of Thermodynamics)
or, dU = W = -300J.
 
Now, for A and B, it is given that the Initial conditions and final conditions for each is the same, so the change in internal energy will also be the same. Hence, For B, dU = -300J
 
Again for B,
From First Law of Thermodynamics,
dU = dQ + dW
=> -300 = dQ – 200
or, dQ = -100 J
 
Thus, Option (B) is the correct answer!
 
Last Activity: 6 Years ago
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