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Grade: 12th pass
        
System A and system B above are identical closed 
 
systems that undergo a change of state from the 
 
same initial conditions (P1, V1, T1) to the same 
 
final conditions (P2, V2, T2), but by a different 
 
process. What are DU and q for the change in 
 
state for system B?
5 months ago

Answers : (2)

Kapil Khare
80 Points
							
Work Done in system A = W = -300J
Since, system A has gone through adiabatic process,
Heat transfer in system A = q = 0
Change in internal energy of A = W =  -300J
 
Since, initial and final condition of A and B are same,
Change in internal energy of A = change in internal energy of B
\implies Change in internal energy of B = -300
 
For system B,
q + W = change in internal energy of B
-200 + q = -300
\implies Heat transformmed = q = -100
5 months ago
Rajdeep
226 Points
							
HELLO THERE!
 
The foremost concept that is going to be used in the question is that, Internal energy is a state function, that does not depend on the path (process) of the system, but on the initial and final state of the system.
 
For A, the process is Adiabatic, so heat exchance Q = 0.
U = Q + W (From First Law of Thermodynamics)
or, dU = W = -300J.
 
Now, for A and B, it is given that the Initial conditions and final conditions for each is the same, so the change in internal energy will also be the same. Hence, For B, dU = -300J
 
Again for B,
From First Law of Thermodynamics,
dU = dQ + dW
=> -300 = dQ – 200
or, dQ = -100 J
 
Thus, Option (B) is the correct answer!
 
5 months ago
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