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Suppose A and B form 2 compounds B2A3 and B2A. If 0.05 mole ofB2A3 weighs 9 g and 0.1 mole ofB2A weighs 10 g, the atomic weight of A and B are

Suvashree Dinda , 8 Years ago
Grade 11
anser 3 Answers
Vikas TU

Last Activity: 8 Years ago

 
molar mass of B2A3 = 9/0.05 = 900/5 
=>180 = 2B + 3A ….....................................(1)
molar mass of B2A = 10/0.1 = 100
=> 100 = 2B + A …...........................................(2)
solve the eqns. (1)  and (2)
2A = 80
A = 40
B = 30
 
 
             

Vamshee krishna

Last Activity: 6 Years ago

let mass of B2A3 be x 
as we know no of moles(n) = given mass / mass of compound 
                 0.05 = 9g / x
                  x = 9 / 0.05 = 180g
           mass of B2A3 is 180g
now,
let mass of B2A be y
                    0.1 = 10 / y
                    y = 10 / 0.1 = 100g
 so,            mass of B2A is 100g.
              now 3B+2A=180
                      B+2A=100
Solving both the eqations we get 2B = 80 and B=40
substituting the value of B in any equation we get A=30

Rishi Sharma

Last Activity: 4 Years ago

Dear Students,
Please find below the solution to above problem.
Let mass of B2A3 be x
As we know no of moles(n) = given mass / mass of compound
0.05 = 9g / x
x = 9 / 0.05 = 180g
mass of B2A3 is 180g
now,
let mass of B2A bey
0.1 = 10 / y
y = 10 / 0.1 = 100g
so, mass of B2A is 100g.
now 3B+2A=180
B+2A=100
Solving both the eqations we get 2B = 80 and B=40
substituting the value of B in any equation we get A=30

Thanks and Regards

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