Vikas TU
Last Activity: 8 Years ago
molar mass of B2A3 = 9/0.05 = 900/5
=>180 = 2B + 3A ….....................................(1)
molar mass of B2A = 10/0.1 = 100
=> 100 = 2B + A …...........................................(2)
solve the eqns. (1) and (2)
2A = 80
A = 40
B = 30