Arun
Last Activity: 5 Years ago
Volume of one virus = voume of cylinder = π r²h
= 22/7 × 7 × 7 × 10 A°³
=22 × 7 × 10 A°³
=1540 × 10^-30 m³
=1.54 × 10^-27 m³
so, volume of one mole of virus = 6.023 × 10²³ × volume of one virus
= 6.023 × 10²³ × 1.54 × 10^-27 m³
= 9.27542 × 10^-4 m³
= 9.27542 × 10² cm³
now, molecular weight = volume of 1mole/ specific volume
= 9.27542 ×10² / 6.02 × 10^-2 g/mol
= 1.54 × 10⁴ g/mol
