Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
Close
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping

Solve this question.............................,...................

Solve this question.............................,...................

Question Image
Grade:12

1 Answers

Khimraj
3007 Points
3 years ago
Number of moles of silver = 200×0.1/1000 = 0.02
where 1 mole silver = 96500 coulomb so,
charge needed = 0.02 × 96500 = 1930 coulomb.
If strength of current  is 0.1A, then,
time needed to remove 50% of silver = 1930 × ½  = 0.1*t
so t = 9650 second.
Hope it clears. If you like anser then please approve it.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Register ICAT

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More