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Number of moles of silver = 200×0.1/1000 = 0.02 where 1 mole silver = 96500 coulomb so, charge needed = 0.02 × 96500 = 1930 coulomb. If strength of current is 0.1A, then, time needed to remove 50% of silver = 1930 × ½ = 0.1*tso t = 9650 second.Hope it clears. If you like anser then please approve it.
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