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        Solve the given question with explanation and reactions involved.
one year ago

Khimraj
2612 Points
							Given DataC(graphite) + O2(g) $\rightarrow$ CO2(g)    $\Delta$H = -395.0KJ            – (1)H2(g) + O2(g) $\rightarrow$ H2O(g)    $\Delta$H = -269.4KJ                    – (2)6C(graphite) + 6H2(g) +3O2(g) $\rightarrow$ CO2(g)    $\Delta$H = -1169.8KJ       – (3)Combustion of glucose is given byC6H12O6(s) + 6O2(g) $\rightarrow$ 6CO2(g) + 6H2O    $\Delta$rH above equation can be obtained by manipulating equation (1),(2) and (3) as6*(1) + 6*(2) – (3)So $\Delta$rH  = 6*(-395.0KJ) + 6*(-269.4KJ) – (-1169.8KJ ) = -2816.6KJ.Hope it clears. If you like answer then please approve it.

one year ago
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