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Grade: 11
        Solve the given question with explanation and reactions involved.
3 months ago

Answers : (1)

Khimraj
1409 Points
							
Given Data
C(graphite) + O2(g) \rightarrow CO2(g)    \DeltaH = -395.0KJ            – (1)
H2(g) + O2(g) \rightarrow H2O(g)    \DeltaH = -269.4KJ                    – (2)
6C(graphite) + 6H2(g) +3O2(g) \rightarrow CO2(g)    \DeltaH = -1169.8KJ       – (3)
Combustion of glucose is given by
C6H12O6(s) + 6O2(g) \rightarrow 6CO2(g) + 6H2O    \DeltarH
 above equation can be obtained by manipulating equation (1),(2) and (3) as
6*(1) + 6*(2) – (3)
So \DeltarH  = 6*(-395.0KJ) + 6*(-269.4KJ) – (-1169.8KJ ) = -2816.6KJ.
Hope it clears. If you like answer then please approve it.
3 months ago
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