Grade 11Physical Chemistry
SOLUTION OF CALCULATING THE EQUIVALENT WEIGHT OF MOHR’S SALT
SOLUTION OF CALCULATING THE EQUIVALENT WEIGHT OF MOHR’S SALT
1 Answer
Bhavya
Dear student
n-factor for a salt is either total cationic charge/total anionic charge excluding the charge on cation/anion of water.
Mohr’s salt(NH₄)₂Fe(SO₄)₂·6H₂O
Here total cationic charge (2 NH4+ and 1 Fe+2) = total anionic charge (2 SO4-2) = 4
Equivalent weight = Molar mass/ n-factor = 392/ 4 = 98
n-factor for a salt is either total cationic charge/total anionic charge excluding the charge on cation/anion of water.
Mohr’s salt(NH₄)₂Fe(SO₄)₂·6H₂O
Here total cationic charge (2 NH4+ and 1 Fe+2) = total anionic charge (2 SO4-2) = 4
Equivalent weight = Molar mass/ n-factor = 392/ 4 = 98
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