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Silver atom has completely filled d orbitals (4d10) in its ground state. How can you say that it is a transition element?

rishav kumar , 11 Years ago
Grade 9
anser 4 Answers
Sumit Majumdar

Last Activity: 10 Years ago

Dear student,
Ag has a completely filled 4dorbital (4d105s1) in its ground state. Now, silver displays two oxidation states (+1 and +2). In the +1 oxidation state, an electron is removed from thes-orboital. However, in the +2 oxidation state, an electron is removed from thed-orbital. Thus, thed-orbital now becomes incomplete (4d9). Hence, it is a transition element.
Regards
Sumit

Thakur Mohini

Last Activity: 6 Years ago

Transition elements are those elements that have unpaired electrons or incomplete d orbitals in its ground state or in any OXIDATION STATE. Silver occur in +2 where 1 electron is removed from d orbital resulting in 4d^9 i.e unpaired electron. So it is a transition element.

Vidyabathy Ravi

Last Activity: 6 Years ago

Silver being a metal can loose its outershell electron but it's its configuration is 4d10 4s1 which is highly stable however it can loose two electrons to under go bonding so that can exist in 4d9 partial ddorbital  configuration. That's why silver is considered as transition metal...
 
Exmaple- AgF2 Silver(II)Flouride

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the answer to the question.
 
Ag has a completely filled 4d orbital (4d105s1) in its ground state.
Now, silver displays two oxidation states (+1 and +2).
In the +1 oxidation state, an electron is removed from the s-orboital.
However, in the +2 oxidation state, an electron is removed from the d-orbital.
Thus, the d-orbital now becomes incomplete (4d9).
Hence, it is a transition element.
 
Hope it helps.
Thanks and regards,
Kushagra

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