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Grade 12th passPhysical Chemistry

Resistance of 0.2 molar solution of an electrolyte is 50 ohms the specific conductance of the solution is 1.3 cm and if resistance of the 0.4 more solution of the same electrolyte is 268 molar conduct

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9 Years agoGrade 12th pass
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ApprovedApproved Tutor Answer1 Year ago

To find the specific conductance of a 0.4 molar solution of the same electrolyte, we can use the relationship between resistance, conductance, and specific conductance. Let's break this down step by step.

Understanding Key Concepts

First, it's important to clarify some terms:

  • Resistance (R): This is the opposition to the flow of electric current, measured in ohms (Ω).
  • Conductance (G): This is the reciprocal of resistance, indicating how easily electricity can flow through a solution, measured in siemens (S).
  • Specific Conductance (κ): This is a measure of a solution's ability to conduct electricity, normalized to a specific concentration, measured in siemens per centimeter (S/cm).

Calculating Conductance

From the information given, we know that the resistance of a 0.2 molar solution is 50 ohms. We can calculate the conductance (G) of this solution using the formula:

G = 1/R

Substituting the values:

G = 1/50 = 0.02 S

Finding Specific Conductance

Next, we can find the specific conductance (κ) of the 0.2 molar solution. Specific conductance is calculated using the formula:

κ = G × (V/L)

Where V is the volume and L is the length of the solution through which the current flows. However, since we are looking for specific conductance per molarity, we can use the relationship:

κ = G × C

Where C is the concentration in molarity. For the 0.2 molar solution:

κ = 0.02 S × 0.2 mol/L = 0.004 S/cm

Applying the Same Logic to the 0.4 M Solution

Now, we need to find the specific conductance for the 0.4 molar solution. We know that the resistance of this solution is given as 268 ohms. Let's calculate its conductance:

G = 1/R = 1/268 ≈ 0.00373 S

Calculating Specific Conductance for the 0.4 M Solution

Using the same formula for specific conductance:

κ = G × C

Substituting the values for the 0.4 molar solution:

κ = 0.00373 S × 0.4 mol/L ≈ 0.001492 S/cm

Summary of Findings

To summarize, the specific conductance of the 0.4 molar solution of the electrolyte is approximately 0.001492 S/cm. This demonstrates how the specific conductance can vary with concentration and resistance, reflecting the electrolyte's ability to conduct electricity in different concentrations.