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`        relation between molarity and molality `
5 years ago

bharat bajaj
IIT Delhi
122 Points
```							Molarity/Molality = (moles of solute/volume of solution) × (mass of solvent/moles of solute)           = mass of solvent (in kg)/volume of solution (in litre)           = mass of solvent (in grams)/volume of solution = W/V  Let the density of the solution be d.   Unit= g mL−1 Mass of solution = V × d Mass of solute = number of moles × molecular mass of solute           = n mAMass of solvent, W = mass of solution – mass of solute           = V × d – n × mA Thus,  Molaity/Molality (M/m) = V×d–n×mA/V  Molaity (m) = molarity×V/V×d–n×mA                     =molaity/d–n/V×mA                   m =molaity/d–molaity×mA where wZ, wBare masses of solvent and solute respectively xAand xBare mole fractions of solvent and solute respectively mAis molecular mass of solvent.ThanksBharat BajajAskiitians faculty
```
5 years ago
Arun Kumar
IIT Delhi
256 Points
```							Hi$\\m={n \over W}={ M \over {1000d-M*M_o \over 1000}}={1000M \over {1000d-M*M_o}} \\where m is molality \\M is no. of moles \\M_o is the molecular mass \\d is density in g/cc$Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
```
5 years ago
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