Vikas TU
Last Activity: 7 Years ago
From 50 ml and 0..06 M of NaBr moles of Br- => 0.06*50/1000 => 0.06/20 = 0.003 moles.
Now from 0.003 moles of Br- we get, the moles of Cl2 => 0.003/2 => 0.0015 moles.
Now Volumerequired would be:
0.0015 = 0.05*V
V => 0.0015/0.05 => 0.03 litre or => 30 ml.