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`        Question no 78  please answer as soon as possible thanks`
one year ago

Arun
18601 Points
```							According to the given question, HCl + NaOH → NaCl + H₂O As per the details that are given in the question, we can calculate the following:-No. of moles of HCl = (40 ml) (0.1 mol/L)= (0.04 L) (0.1 mol/L) = 0.004 molesNo. of moles of NaOH = (10 ml) (0.45 mol/L)= (0.01 L) (0.45 mol/L) = 0.0045 molesTherefore, excess amount of NaOH will be = 0.0045 moles - 0.004 moles= 0.0005 moles Thus, the total volume will be = 0.04 L + 0.01 L = 0.05 L Molarity of OH will be = 0.0005 moles/0.05 L = 0.01 MpOH = -log [OH] = -log 0.01 Therefore, pOH = 2 so, pH = 14 - pOH Thus, pH of the above solution is = 12
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one year ago
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