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Que- In a photoelectric experiment the collector plate is at 2V with respect to emitter plate made of copper (work function 4•5 eV) .The emitter is illuminated by a source of monochromatic light of wavelength 200nm. Find the min KE and maxKE of photoelectrons reaching the collector

Que-
In a photoelectric experiment the collector plate is at 2V with respect to emitter plate made of copper (work function 4•5 eV) .The emitter is illuminated by a source of monochromatic light of wavelength 200nm. Find the min KE and maxKE of photoelectrons reaching the collector
 

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Grade:11

1 Answers

Arun
25763 Points
2 years ago
Dear student
 
 ∅ = 4.5 eV, λ = 200 nm Stopping potential or energy = E - ∅ = WC/λ - ∅ Minimum 1.7 V is necessary to stop the electron The minimum K.E. = 2eV [Since the electric potential of 2 V is reqd. to accelerate the electron to reach the plates] the maximum K.E. = (2+1, 7)ev = 3.7 ev.
 
Regards
Arun (askIITians forum expert)

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