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        Qn. In haber process 30 litres of dihydrogen and 30 litres of dinitrogen were taken         for reaction which yielded only 50% of the expected product. What will be the composition of gaseous mixture under the aforesaid condition in the end?
2 years ago

Arun
23340 Points
							Dear student N2 (g) +3 H2(g) →2 NH3According to the Gay Lussac law , 1 L of the N2 gas would react with 3 L of H2 gas to produce 2 L of NH3.Since 30 L of N2 and 30 L of H2 gas are present thus according to the balanced equation H2 is the limiting reagent .Thus 30 L H2 gas on reaction with 10 L N2should produce 20 L NH3. But since it is given that only 50% of the expected product is obtained . This shows that only 15 L of H2 gas is reacting with 5 L N2 gas to give half of the expected product i.e. 10 LNH3 gas.Thus composition of gases in the reaction mixture : Amount of N2 gas left in the reaction vessel = 30-5 = 25 LAmount of H2 gas left in the reaction vessel = 30-15 = 15 LAmount of NH3 gas produced in the reaction vessel = 10 L RegardsArun (askIITians forum expert)

2 years ago
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