Q1. Which among the following factor is the most important in making F the strongest oxidising agent?

a hydration enthalpy

b elctron gain enthalpy

c ionisation enthalpy

d bond dissociation enthalpy

ans is option d but why sir??

Q2. If the aufbau principle is not being followed , Ca(Z=20) wud have been placed in

a s block

b p block

c d block

d f block

Q3. Lower oxidation state is stable when difference in ionisation potential is about

a 14eV

b 16eV

c 10eV

d 18eV

PLEASE GIVE ME RESONS FOR THE ANSWERS.

Q1
ans-because the weak bond enthalpy it easily form F- ion which makes it the strongest oxidising agent .Due to repulsion between the lone pair of electron on the two atoms.It makes the molecule less reactive and hence it forms F- ion easily
Q2(c)
Z=40
Electronic configuration withou afbau principle
1s^2 2s^2 2p^6 3s^2 3p^6 3d^2
so the last electron enters in d orbital it should be dblock element

Q3(b)
If the difference between IP<15ev then higher oxidation state will be stable but if the difference >16ev (Na+>Na+2)then lower oxidation state will be stable