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Q.79 You have to calculate the pH of a 0.1 M NH4OH having dissociation constant kB - 1.0 × 10-5 is equal to ??

Q.79
You have to calculate the pH of a 0.1 M NH4OH having dissociation constant kB - 1.0 × 10-5 is equal to ??
 
 

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Grade:12

1 Answers

Vikas TU
14149 Points
4 years ago
Hiii Tejal
pH = – log [H+]
14-pH = – log[OH-]
alpha = sqrt(Kb/c)
alpha = 0.01
pH = -log(sqrt(Kb*C)
pH=6

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