Arun
Last Activity: 6 Years ago
We know Tb° of pure water at 1 atm is 100°C and Tb is given100.130 °C so we can calculate ΔTb by using equation 1. Then by using equation 2 we can calculate m and then we can find out the molecular weight of solute or we can directly calculate it by using equation 4.
ΔTb = Tb - Tb°
ΔTb = 100.130 °C - 100 °C = 0.130 °C
ΔTb = Kb × m
m = 0.130 °C / 0.513°Cm-1 = 0.253 mol Kg-1
Molality m = w2 × 1000
M2 × w1
M2 = w2 × 1000
m × w1
M2 = 3.24g × 1000
0.253 mol Kg-1 × 200
M2 = 64.03 g/mol
