KSK
Last Activity: 9 Years ago
mole of potassium = wt of sample ÷ atomic mass
= 4 ÷ 39 = 0.102
no. of atoms = moles × avogadro’s no.
= 0.102 × 6.022 × 10^23
BCC lattice contains total of 2 atoms : (1/8) contribution of each of 8 corner atoms gives 1 + 1 at body centre, i.e., intersection of body diagonals.
no. of unit cells = total atoms ÷ atoms per unit cell
= (0.102 × 6.022 × 10^23) ÷ 2
= 0.102 × 3.011 × 10^23
= 3.07122 × 10^22
