Grade 10Physical Chemistry
PLZ explain above attached question in detail it`s urgent PLZ
1 Answer
somi teez
hi,SRISHU
moles of gypsum in 1.0 g=given mass/atomic mass
=1/172 moles
now,
moles of CaSO4 in 0.791 g=0.791/136.14=0.006 moles(approx)
amount of water=1g-0.791g=0.209g
moles of water present=0.209/18=0.016
so,actual moles of caso4=0.16/0.006=2 moles (approx)
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