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Grade: 12
        
Pls solbe this questions .Please write the reactiom also
Thanks 
 
24 days ago

Answers : (1)

Arun
16176 Points
							

 MnO2   +             4HCl       →           MnCl2                +             Cl2

Cl2        +             2KI          →           2KCl                   +             I2

I2         +             2Na2S2O3 →        2NaI                      +             Na2S4O6

Redox change are :

2e           +             I2           →           2I-

2(S2+)2                                 →           (S5/2+)4 +             2e

2e           +             Mn4+      →           Mn2+

The above reaction suggest that,

Meq. of MnO2                   =             Meq. of Cl2formed

=             Meq. of I2 liberated    

=             Meq. of Na2S2O3 used

Therefore,          [w/(M/2)] × 1000             =             0.1 × 1 × 30

[ NNa2S2O3= MNa2S2O3, as, valency factor = 1]

Or,         w            =             (0.1 × 1 × 30 × M)/200

=             (0.1 × 1 × 30 × 87)/200

=             0.1305

Therefore,          Purity of MnO2                  =             (0.1305/0.5) × 100

=             26.1%            

24 days ago
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