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Please solve the problem in the attachment. ............................. ............................ ..,

Pawan joshi , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun
Solubility product (Ksp)=(Ag3+)(PO4^3-)=C^2
 
Molar conductivity(m)=Equivalent conductivity× equivalent factor of the electrolyte(i.e. 3 in this case) and C=Conductance/m.
 
So,Ksp =((9×10^-6)/(1.50×10^-4))^2
 
 
Last Activity: 6 Years ago
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