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Grade 12Physical Chemistry

Please solve question no 29 that is question on activation energy

Question image for Please solve question no 29 that is question on ac
Profile image of vijay kumar
9 Years agoGrade 12
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1 Answer

Profile image of Vikas TU
9 Years ago
From the activation energy formulae:
AT temperature 400 K, the time constant is with Ea activation energy,
K = Z*e^(-Ea/400R)............(1)
and
after decreasing we get,
AT temperature 300 K, the time constant is with Ea activation energy,
k = ze^(-0.05xEa/300R)..................(2)
Solving both the eqns. we get,
0.05x = 0.75
or
x = 15.