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`        Please sir solve this question. It is from AIATS.Please......sir solve it .........I am posting ot 4th time.......please sir its my humble request to aolve this question.1.2 gm Mg is burnt in a closed vessel whixh contain 0.5gm of O2.Millilitres of 0.25M H2So4 required t dissolve the residue in the vessel is Ans200ml(please sir solve it in terms of mole not in equivalent mole.I have a little confusion what we mean by residue here)please sir solve it as I am completely dependent on Askiitian. please sir solve it.`
one year ago

Avni Chauhan
247 Points
```							Mg is burnt in air implies reaction is 2Mg + O2----> 2MgOmoles of Mg = 0.05moles of oxygen = 0.0151 mole of oxygen reacts with 2 moles of Mg , therefore oxygen is the limiting reagent and will react with 0.03moles of Mg to produce 0.03 moles of MgO.This MgO will be reacting with sulphuric acid.MgO + H2SO4------> MgSO4+ H2OSo we require 0.03 moles of sulphuric acid. Molarity x volume = moles0.25 x V = 0.03V = 0.12L = 120mLTHe left Mg will then react with the acid. Mg + H2SO4----> MgSO4+ H20.02 moles of Mg will require 0.02 moles of acid0.25 x V = 0.0280mLtotal acid required = 200mLP.S. It is not sir..it’s ma’am :)
```
one year ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions