Please sir solve this question. It is from AIATS.Please......sir solve it .........I am posting ot 4th time.......please sir its my humble request to aolve this question.1.2 gm Mg is burnt in a closed vessel whixh contain 0.5gm of O₂.Millilitres of 0.25M H₂So₄ required t dissolve the residue in the vessel is

Ans200ml(please sir solve it in terms of mole not in equivalent mole.I have a little confusion what we mean by residue here)please sir solve it as I am completely dependent on Askiitian. please sir solve it.

Mg is burnt in air implies reaction is 2Mg + O₂----> 2MgO

moles of Mg = 0.05
moles of oxygen = 0.015
1 mole of oxygen reacts with 2 moles of Mg , therefore oxygen is the limiting reagent and will react with 0.03moles of Mg to produce 0.03 moles of MgO.
This MgO will be reacting with sulphuric acid.
MgO + H₂SO₄------> MgSO₄+ H₂O
So we require 0.03 moles of sulphuric acid. Molarity x volume = moles
0.25 x V = 0.03
V = 0.12L = 120mL

THe left Mg will then react with the acid. Mg + H₂SO₄----> MgSO₄+ H₂
0.02 moles of Mg will require 0.02 moles of acid
0.25 x V = 0.02
80mL
total acid required = 200mL


P.S. It is not sir..it’s ma’am :)