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Grade: 12

                        

Please reply fast please please please please please

2 years ago

Answers : (1)

Arun
25122 Points
							
 

O—→ ON + Oexcited

O2 —→ ON + ON

E = 498 x 103 J / mole

= 498 x 103 / 6.023 x 1023J  per molecule = 8.268 x 10–19 J

Energy required for excitation = 1.967 eV = 3.146 ´10–19J

Total energy required for photochemical dissociation ofO2

= 8.268 x 10–19 + 3.146 x 10–19   = 11.414 x 10–19 J hc/λ = 11.414 x 10–19J

λ = 6.626 x 10-34x 3 x 108 / 11.414 x 10-19= 1.7415 x 10–7 m = 1741.5 Å          

2 years ago
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