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Please provide a detailed solution for this question.Pg 109 c4.

ANMOL SETH , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

From the colligative property =Po-Ps/Po=n2/n1
moles of glucose =  18/180 = 0.1 and
moles of water = 178.2/18 = 9.99
Hecne at 100 degree celsium pressure of soln bein 760 torr.
Therfore, (P0 – 1)/P0 = 0.1/9.99
1 – 0.01001 = 1/P0
P0 = 1/0.98998 = > 1.1010 atm or => 1.1010*760 => 767.69 torr.
 

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