To answer this type question firstly we should know that: Charge on NH3 =0(zero)
Charge on H2O=0(zero)
Charge on CO =0 (zero)
Please note that CO(carbonyl group) is different from the Co(Cobalt).
So now if we look at the 3rd option.
In Ni(CO)4 we will put oxidation state of CO = 0 and for Ni we will put x which we have to find.
So now X + 4*(0) = 0
X + 0 = 0
X = 0
That means oxidation state of Ni in Ni(CO)4 is 0(zero)
Regards
Askiitian member
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