please help with this question......................
please help with this question......................
Rushil , 7 Years ago
Grade 12
Physical Chemistry> please help with this question..............
1 Answers
Arun
Dear student
1) We must first find the molarity of the solute:
Referring the periodic table :
atomic mass of = 105.96 g/mol (Summing inidividual atomic masses of Sodium, Carbon and Oxygen)
Number of moles of = No. of grams of dissolved x ( 1 / atomic mass )
Number of moles of = 25.3 x ( 1 / 105.96 ) = 0.238 mol
Now, to find number of mol of in given solution,
= No. of moles of / volume in Litres
= 0.238 / 0.25 = 0.952 mol /L (To convert 250 ml to L we divide by 1000 as 1000 ml = 1 L)
2) Finding the number of ions :
→ 2 +
So we get 2 moles of sodium and 1 mole of carbonate in 1 mol of solution of sodium Carbonate
3) Finding molarity :
Molarity of sodium ion is = No. of moles of Sodium ion x = 2 x 0.952 = 1.904 moles of / Litre = 1.904 M
Molarity of Carbonate ion is = No. of moles of Carbonate ion x = 1 x 0.952 = 0.952 moles of Carbonate ion / Litre = 0.952 M
molar concentration Of sodium ion and carbonate ion are 1.904 M & 0.952 M respectively
Regards
Arun (askIITians forum expert)
Approved Last Activity: 7 Years ago
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