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2 years ago

## Answers : (1)

Susmita
425 Points
							Electron of charge -e moves in a circular path of radius r with velocity v under the attraction of nucleus of charge Ze.Coulomb attraction=cetripetal force.Force equation$\frac{Ze.e}{4\pi \epsilon r^2}=\frac{mv^2}{r}$       ........(1)The potential energy U is simply this Coulomb potential.$U=\frac{-Ze.e}{4\pi \epsilon r}$Kinetic energy$K=\frac{1}{2}mv^2=\frac{Ze.e}{8\pi \epsilon r}$using the value of mv^2 from previous eq1. From Bohr 2nd postulateL=nh/2piOr,mvr=nh/2piOr,r=nh/2pimv Use this in eq1 to obtain v.Also remember that hydrogen spectrum is discrete because of this quantization.we get line spectrum,eg,lyman balmer etc.it is not continuous.

2 years ago
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