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Grade: 10

                        

Please help me with the question . How to answer it

2 years ago

Answers : (1)

Susmita
425 Points
							
Electron of charge -e moves in a circular path of radius r with velocity v under the attraction of nucleus of charge Ze.Coulomb attraction=cetripetal force.
Force equation
\frac{Ze.e}{4\pi \epsilon r^2}=\frac{mv^2}{r}       ........(1)
The potential energy U is simply this Coulomb potential.
U=\frac{-Ze.e}{4\pi \epsilon r}
Kinetic energy
K=\frac{1}{2}mv^2=\frac{Ze.e}{8\pi \epsilon r}
using the value of mv^2 from previous eq1.
 
From Bohr 2nd postulate
L=nh/2pi
Or,mvr=nh/2pi
Or,r=nh/2pimv 
Use this in eq1 to obtain v.
Also remember that hydrogen spectrum is discrete because of this quantization.we get line spectrum,eg,lyman balmer etc.it is not continuous.
 
2 years ago
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