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Grade: 12th pass
        Please answer the question shown in above image. Pls
10 months ago

Answers : (1)

Chhavi Jain
92 Points
							
Dear Student ,
 
Hypo solution( Na2S2O3 ) reacts with I according to the following rxn :
 
2 Na2S2O3   +    I2     -------->   2NaI      +     Na2S4O6
    xf = 1
N= 1/10, 15.7 mL
 
using , N= M * xf
           0.1 = M *1 
            M= 0.1 
Now, molarity (M) = no.of moles of solute / vol. of solution in L
                0.1 = n * 15.7 * 10-3 
                 n = 6.36 moles of Na2S2O3 
 
According to the reaction moles of I2 required  = 6.36 / 2 = 3.18 moles
 
now consider the eqbm given :
 
                                 2H     ---->              H2         +         I2
                          t=0   n = 0.96/ 128         –                      – 
                                     =0.0075
                
                          t= eqbm   0.0075 – 2x        x                 x                moles
 
and we know the value of x = 3.18 moles 
  
Now,  degree of dissociation = (  final moles / initial moles ) * 100
                                                 
Hope this will help you.
 
10 months ago
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