Osmotic pressure of a 5% of a solution of cane sugar at 342K
Pooja gupta , 5 Years ago
Grade 12th pass
Physical Chemistry> Osmotic pressure of a 5% of a solution of...
2 Answers
Arun
Last Activity: 5 Years ago
5% means in 100 ml of solvent there is 5 g of solute, T=288 K,RMM=342g/mol, r=0.0821 lit atm K-1mol-1
C is molarity, i.e no of moles of solute in a litre of solution
we have pi=CRT
=5/342*0.1 *0.0821 *288= 3.45 atm
Vikas TU
Last Activity: 5 Years ago
Dear student
m = mol. mass of sucrose (C12H22O11) = 342
w = 5 g, V = 100 mL = 0.1 litre
S = 0.082, T = (15 + 273) = 288 K
Applying the equation PV = w/m ST,
P = 5./342 × 1/0.1 × 0.082 × 288
= 3.453 atm
w = 5 g, V = 100 mL = 0.1 litre
S = 0.082, T = (15 + 273) = 288 K
Applying the equation PV = w/m ST,
P = 5./342 × 1/0.1 × 0.082 × 288
= 3.453 atm
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