 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
osmotic pressure of 40% (mass/vol.) urea solution is 1.64 atm and that 3.42%(mass/vol.) cane-sugar is 2.46 atm . when equal volumes of the above two solutions are mixed, the osmotic pressure of the resulting solution is _____

```
4 years ago

```							let M1 be the molarity of urea soln. and M2 be the molarity for Cane -sugar soln. respectively.Of equal volumes would be mixed then,M1V + M2V = M(2V)M = (M1+M2)/2 would be the new concentration. From first soln.1.64 =M1STor M1 = 1.64/STsimilarlyM2 = 2.46/STPut it in M.then apply for mixed soln.O.P = 1*M*S*TS*T would be cancelled out.
```
4 years ago
```							Yes,let M1 be the molarity of urea soln. and M2 be the molarity for Cane -sugar soln. respectively.Of equal volumes would be mixed then,M1V + M2V = M(2V)M = (M1+M2)/2 would be the new concentration. From first soln.1.64 =M1STor M1 = 1.64/STsimilarlyM2 = 2.46/STPut it in M.then apply for mixed soln.O.P = 1*M*S*TS*T would be cancelled out.
```
3 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions