One mole of KClO3 is heated in presence of MnO2. The produced oxygen is used inburning of Al Then oxide of that will be formed will be

When one mole of potassium chlorate (KClO3) is heated in the presence of manganese dioxide (MnO2), it decomposes to produce potassium chloride (KCl) and oxygen gas (O2). The reaction can be represented as follows:

Decomposition of KClO3

The balanced chemical equation for this decomposition is:

• 2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)

In this reaction, manganese dioxide acts as a catalyst, speeding up the decomposition without being consumed in the process. The oxygen gas produced can then be used for combustion reactions, such as burning aluminum (Al).

Combustion of Aluminum

When aluminum burns in the presence of oxygen, it forms aluminum oxide (Al2O3). The balanced equation for this combustion reaction is:

• 4 Al (s) + 3 O2 (g) → 2 Al2O3 (s)

From this equation, you can see that four moles of aluminum react with three moles of oxygen to produce two moles of aluminum oxide. Therefore, the amount of aluminum oxide formed depends on the amount of oxygen available from the decomposition of KClO3.

Calculating the Amount of Oxygen Produced

From the decomposition of one mole of KClO3, we obtain three moles of oxygen gas. This is crucial because it determines how much aluminum can react. Since the combustion of aluminum requires oxygen, we can calculate how much aluminum can be burned with the oxygen produced.

Using Stoichiometry

Given that three moles of O2 are produced, we can find out how many moles of aluminum can react:

• 3 moles of O2 will react with (4/3) * 3 = 4 moles of Al.

Thus, if you have enough aluminum available, you can burn 4 moles of aluminum using the oxygen generated from one mole of KClO3.

Final Product: Aluminum Oxide

As a result of burning aluminum in the oxygen produced, the final product will be aluminum oxide (Al2O3). The stoichiometry of the reaction indicates that for every 4 moles of aluminum burned, 2 moles of aluminum oxide are formed:

• 2 moles of Al2O3 will be produced from 4 moles of Al.

In summary, when one mole of KClO3 is heated in the presence of MnO2, it produces oxygen gas, which can then be used to burn aluminum, resulting in the formation of aluminum oxide (Al2O3) as the final product. This process illustrates the interconnectedness of chemical reactions and how products from one reaction can serve as reactants in another.