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One mole of an ideal gas is heated at constant pressure from 0oC to 100oC then work done will be
2 years ago

Vikas TU
8753 Points

W = nR(T2 – T1) => 1*R*(100 – 0) => 100R J would be the work done for One mole of an ideal gas when heated at constant pressure.
2 years ago
Daniel Livingston
11 Points
W=-P.∆v    =-P(V2-V1)    =-P{(nRT2÷P)-(nRT1÷P)}    =-nR(T2-T1)    =-1×1.987(373-273)    =-1.987(100)    =-198.7 cal    =-198.7×4.184 Joules    =-831.3608 Joules

one year ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions