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One mole of an ideal gas is heated at constant pressure from 0oC to 100oC then work done will be

One mole of an ideal gas is heated at constant pressure from 0oC to 100oC then work done will be

Grade:11

3 Answers

Vikas TU
14149 Points
7 years ago
W = nR(T2 – T1) => 1*R*(100 – 0) => 100R J would be the work done for One mole of an ideal gas when heated at constant pressure.
Daniel Livingston
11 Points
6 years ago
W=-P.∆v =-P(V2-V1) =-P{(nRT2÷P)-(nRT1÷P)} =-nR(T2-T1) =-1×1.987(373-273) =-1.987(100) =-198.7 cal =-198.7×4.184 Joules =-831.3608 Joules
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the solution to your problem.
 
W = – P.∆V
= – P(V2 – V1)
= – P{(nRT2÷P) – (nRT1÷P)}
= – nR(T2 – T1)
= – 1×1.987(373 – 273)
= – 1.987(100)
= – 198.7 cal
= – 198.7 × 4.184 Joules
= – 831.3608 Joules
 
Thanks and regards,
Kushagra

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