One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular weight of mass of 44 u. The alkene is
Vicki Sharma
12 Years agoGrade 12
2 Answers
Sunil Kumar FP
11 Years ago
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular weight of mass of 44 u. The alkene is CH3CH=CHCH3 +O3 ------2CH3CHO molecular mass of CH3CHO is 12*2+4*1+16 =44 Thus the alkene is 2 butene and the aldehyde formed is ethanal(acetaldehyde)
SHIRIN SAXENA
6 Years ago
In aldehyde cHO is must(mw=29)so remaining is CH3(15), so two ch3cho will form, thus alkene should be but-2-ene.