MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
one mol of Mg in vapour state absorbed 1200 KJ energy. If the first and 2nd ionisation enthalpies of Mg r 750 and 1450 KJ mol^-1 respectively, the final composition of the mixture is
  1. 69% Mg+, 31% Mg2+
  2. 59% Mg+,41% Mg2+
  3. 49% mg+ 51 mg 2+
  4. 29 mg+ 71% mg2+
4 years ago

Answers : (1)

Ashutosh Sharma
askIITians Faculty
181 Points
							it’s answer is (1).
as this ionisation is an endergonic or energy-absorbing process andIst IP < IInd IP < IIIrd IP because as the electrons go out of the atom, the ionic size goes on decreasing and the amount of positive charge goes on increasing because of which positive charge contibution goes on decreasing in the final composition as the atomic size also decreases.
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details