On passing electricity through dilute H2SO4 solution the amount of substances librated at the cathode and are in what ratio? 1. 1:82. 8:13. 16:14. 1:16

During electrolysis of Dilute H2SO4 solution , Hydrogen is liberated at cathode and Oxygen is liberated at anode. Since amount of substances liberated at electrode is in the ratio of their equivalent weights.Therefore , ratio would be 1:8 ( Since Equivalent weight of Hydrogen is 1 and that of Oxygen is 8 )

First by Faraday second law... if the same amount of charge is passing through the solution connected in series for same time then amount of substances deposited is directly proportional to their equivalent weight..........t..your ans.in dilute h2so4. At cathode hydrogen present and at anode oxygen in present in their molecular form.....weight deposited is directly portion all to their equivalent weigt....for hydrogen 2/2=1and for O2 it is 32/4=8. So the answer is1:8.for is 4 is n factor for oxygen an 2 is n factor for hydrogen.