badge image

Enroll For Free Now & Improve your performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

On heating 0.220g of a metallic oxide in hydrgen,0.045g of water is formed.If the equivalent weight of the metal is E, then what is the value of E/9?

4 years ago

Answers : (1)

Bhavya
askIITians Faculty
1286 Points
							Dear student
Let the metallic oxide be MO
MO + H2 -----> H2O + M
Now, by law of equivalence i know that,
equivalence of MO = equivalence of H2O
weight of MO/Equivalent weight of MO = weight of H2O/equivalence of H2O
0.22/ E + 8 = 0.045 / 9
On solving you will get,
E/9 = 4
4 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details