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On heating 0.220g of a metallic oxide in hydrgen,0.045g of water is formed.If the equivalent weight of the metal is E, then what is the value of E/9? On heating 0.220g of a metallic oxide in hydrgen,0.045g of water is formed.If the equivalent weight of the metal is E, then what is the value of E/9?
Dear studentLet the metallic oxide be MOMO + H2 -----> H2O + MNow, by law of equivalence i know that, equivalence of MO = equivalence of H2O weight of MO/Equivalent weight of MO = weight of H2O/equivalence of H2O 0.22/ E + 8 = 0.045 / 9 On solving you will get, E/9 = 4
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